564-7.48x+0.029x^2=176

Solution for 564-7.48x+0.029x^2=176 equation:

564-7.48x+0.029x^2=176

We move all terms to the left:

564-7.48x+0.029x^2-(176)=0

We add all the numbers together, and all the variables

0.029x^2-7.48x+388=0

a = 0.029; b = -7.48; c = +388;
Δ = b2-4ac
Δ = -7.482-4·0.029·388
Δ = 10.9424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7.48)-\sqrt{10.9424}}{2*0.029}=\frac{7.48-\sqrt{10.9424}}{0.058}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7.48)+\sqrt{10.9424}}{2*0.029}=\frac{7.48+\sqrt{10.9424}}{0.058}
$